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5(x+4)=2(x-15)
We move all terms to the left:
5(x+4)-(2(x-15))=0
We multiply parentheses
5x-(2(x-15))+20=0
We calculate terms in parentheses: -(2(x-15)), so:We get rid of parentheses
2(x-15)
We multiply parentheses
2x-30
Back to the equation:
-(2x-30)
5x-2x+30+20=0
We add all the numbers together, and all the variables
3x+50=0
We move all terms containing x to the left, all other terms to the right
3x=-50
x=-50/3
x=-16+2/3
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