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5(x+4)=3(x-4)
We move all terms to the left:
5(x+4)-(3(x-4))=0
We multiply parentheses
5x-(3(x-4))+20=0
We calculate terms in parentheses: -(3(x-4)), so:We get rid of parentheses
3(x-4)
We multiply parentheses
3x-12
Back to the equation:
-(3x-12)
5x-3x+12+20=0
We add all the numbers together, and all the variables
2x+32=0
We move all terms containing x to the left, all other terms to the right
2x=-32
x=-32/2
x=-16
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