5(x+4)=7(2x+1)

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Solution for 5(x+4)=7(2x+1) equation: 



5(x+4)=7(2x+1)

We move all terms to the left:

5(x+4)-(7(2x+1))=0

We multiply parentheses

5x-(7(2x+1))+20=0



We calculate terms in parentheses: -(7(2x+1)), so:

7(2x+1)

We multiply parentheses

14x+7

Back to the equation:

-(14x+7)



We get rid of parentheses

5x-14x-7+20=0

We add all the numbers together, and all the variables

-9x+13=0

We move all terms containing x to the left, all other terms to the right

-9x=-13

x=-13/-9

x=1+4/9

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