5(x+5)+2=8(2x-5)+22

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Solution for 5(x+5)+2=8(2x-5)+22 equation: 



5(x+5)+2=8(2x-5)+22

We move all terms to the left:

5(x+5)+2-(8(2x-5)+22)=0

We multiply parentheses

5x-(8(2x-5)+22)+25+2=0



We calculate terms in parentheses: -(8(2x-5)+22), so:

8(2x-5)+22

We multiply parentheses

16x-40+22

We add all the numbers together, and all the variables

16x-18

Back to the equation:

-(16x-18)



We add all the numbers together, and all the variables

5x-(16x-18)+27=0

We get rid of parentheses

5x-16x+18+27=0

We add all the numbers together, and all the variables

-11x+45=0

We move all terms containing x to the left, all other terms to the right

-11x=-45

x=-45/-11

x=4+1/11

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