5(x+5)+4=-10(x-2)-7

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Solution for 5(x+5)+4=-10(x-2)-7 equation: 



5(x+5)+4=-10(x-2)-7

We move all terms to the left:

5(x+5)+4-(-10(x-2)-7)=0

We multiply parentheses

5x-(-10(x-2)-7)+25+4=0



We calculate terms in parentheses: -(-10(x-2)-7), so:

-10(x-2)-7

We multiply parentheses

-10x+20-7

We add all the numbers together, and all the variables

-10x+13

Back to the equation:

-(-10x+13)



We add all the numbers together, and all the variables

5x-(-10x+13)+29=0

We get rid of parentheses

5x+10x-13+29=0

We add all the numbers together, and all the variables

15x+16=0

We move all terms containing x to the left, all other terms to the right

15x=-16

x=-16/15

x=-1+1/15

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