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5(x+5)+x+2=7(x+4)-(x+1)
We move all terms to the left:
5(x+5)+x+2-(7(x+4)-(x+1))=0
We add all the numbers together, and all the variables
x+5(x+5)-(7(x+4)-(x+1))+2=0
We multiply parentheses
x+5x-(7(x+4)-(x+1))+25+2=0
We calculate terms in parentheses: -(7(x+4)-(x+1)), so:We add all the numbers together, and all the variables
7(x+4)-(x+1)
We multiply parentheses
7x-(x+1)+28
We get rid of parentheses
7x-x-1+28
We add all the numbers together, and all the variables
6x+27
Back to the equation:
-(6x+27)
6x-(6x+27)+27=0
We get rid of parentheses
6x-6x-27+27=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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