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5(x+5)-2(x-3)=3(x+1)+4(2x-1)
We move all terms to the left:
5(x+5)-2(x-3)-(3(x+1)+4(2x-1))=0
We multiply parentheses
5x-2x-(3(x+1)+4(2x-1))+25+6=0
We calculate terms in parentheses: -(3(x+1)+4(2x-1)), so:We add all the numbers together, and all the variables
3(x+1)+4(2x-1)
We multiply parentheses
3x+8x+3-4
We add all the numbers together, and all the variables
11x-1
Back to the equation:
-(11x-1)
3x-(11x-1)+31=0
We get rid of parentheses
3x-11x+1+31=0
We add all the numbers together, and all the variables
-8x+32=0
We move all terms containing x to the left, all other terms to the right
-8x=-32
x=-32/-8
x=+4
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