5(x+6)-7=3+(x-2)

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Solution for 5(x+6)-7=3+(x-2) equation: 



5(x+6)-7=3+(x-2)

We move all terms to the left:

5(x+6)-7-(3+(x-2))=0

We multiply parentheses

5x-(3+(x-2))+30-7=0



We calculate terms in parentheses: -(3+(x-2)), so:

3+(x-2)

determiningTheFunctionDomain
(x-2)+3

We get rid of parentheses

x-2+3

We add all the numbers together, and all the variables

x+1

Back to the equation:

-(x+1)



We add all the numbers together, and all the variables

5x-(x+1)+23=0

We get rid of parentheses

5x-x-1+23=0

We add all the numbers together, and all the variables

4x+22=0

We move all terms containing x to the left, all other terms to the right

4x=-22

x=-22/4

x=-5+1/2

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