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5(x+6)=4x(x+7)
We move all terms to the left:
5(x+6)-(4x(x+7))=0
We multiply parentheses
5x-(4x(x+7))+30=0
We calculate terms in parentheses: -(4x(x+7)), so:We get rid of parentheses
4x(x+7)
We multiply parentheses
4x^2+28x
Back to the equation:
-(4x^2+28x)
-4x^2+5x-28x+30=0
We add all the numbers together, and all the variables
-4x^2-23x+30=0
a = -4; b = -23; c = +30;
Δ = b2-4ac
Δ = -232-4·(-4)·30
Δ = 1009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{1009}}{2*-4}=\frac{23-\sqrt{1009}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{1009}}{2*-4}=\frac{23+\sqrt{1009}}{-8} $
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