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5(x+7)=25+x+(x+7)
We move all terms to the left:
5(x+7)-(25+x+(x+7))=0
We multiply parentheses
5x-(25+x+(x+7))+35=0
We calculate terms in parentheses: -(25+x+(x+7)), so:We get rid of parentheses
25+x+(x+7)
determiningTheFunctionDomain x+(x+7)+25
We get rid of parentheses
x+x+7+25
We add all the numbers together, and all the variables
2x+32
Back to the equation:
-(2x+32)
5x-2x-32+35=0
We add all the numbers together, and all the variables
3x+3=0
We move all terms containing x to the left, all other terms to the right
3x=-3
x=-3/3
x=-1
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