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5(x+8)(x+13)=0
We multiply parentheses ..
5(+x^2+13x+8x+104)=0
We multiply parentheses
5x^2+65x+40x+520=0
We add all the numbers together, and all the variables
5x^2+105x+520=0
a = 5; b = 105; c = +520;
Δ = b2-4ac
Δ = 1052-4·5·520
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-25}{2*5}=\frac{-130}{10} =-13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+25}{2*5}=\frac{-80}{10} =-8 $
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