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5(x+9)-4=12-(x+1)
We move all terms to the left:
5(x+9)-4-(12-(x+1))=0
We multiply parentheses
5x-(12-(x+1))+45-4=0
We calculate terms in parentheses: -(12-(x+1)), so:We add all the numbers together, and all the variables
12-(x+1)
determiningTheFunctionDomain -(x+1)+12
We get rid of parentheses
-x-1+12
We add all the numbers together, and all the variables
-1x+11
Back to the equation:
-(-1x+11)
5x-(-1x+11)+41=0
We get rid of parentheses
5x+1x-11+41=0
We add all the numbers together, and all the variables
6x+30=0
We move all terms containing x to the left, all other terms to the right
6x=-30
x=-30/6
x=-5
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