5(x+I)+4=2(x-3)

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Solution for 5(x+I)+4=2(x-3) equation:


Simplifying
5(x + I) + 4 = 2(x + -3)

Reorder the terms:
5(I + x) + 4 = 2(x + -3)
(I * 5 + x * 5) + 4 = 2(x + -3)
(5I + 5x) + 4 = 2(x + -3)

Reorder the terms:
4 + 5I + 5x = 2(x + -3)

Reorder the terms:
4 + 5I + 5x = 2(-3 + x)
4 + 5I + 5x = (-3 * 2 + x * 2)
4 + 5I + 5x = (-6 + 2x)

Solving
4 + 5I + 5x = -6 + 2x

Solving for variable 'I'.

Move all terms containing I to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + 5I + -4 + 5x = -6 + -4 + 2x

Reorder the terms:
4 + -4 + 5I + 5x = -6 + -4 + 2x

Combine like terms: 4 + -4 = 0
0 + 5I + 5x = -6 + -4 + 2x
5I + 5x = -6 + -4 + 2x

Combine like terms: -6 + -4 = -10
5I + 5x = -10 + 2x

Add '-5x' to each side of the equation.
5I + 5x + -5x = -10 + 2x + -5x

Combine like terms: 5x + -5x = 0
5I + 0 = -10 + 2x + -5x
5I = -10 + 2x + -5x

Combine like terms: 2x + -5x = -3x
5I = -10 + -3x

Divide each side by '5'.
I = -2 + -0.6x

Simplifying
I = -2 + -0.6x

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