5(x-0.4)=(0.5x-0.5)/2

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Solution for 5(x-0.4)=(0.5x-0.5)/2 equation:



5(x-0.4)=(0.5x-0.5)/2
We move all terms to the left:
5(x-0.4)-((0.5x-0.5)/2)=0
We multiply parentheses
5x-((0.5x-0.5)/2)-2=0
We multiply all the terms by the denominator
5x*2)-((0.5x-0.5)-2*2)=0
We add all the numbers together, and all the variables
5x*2)-((0.5x-0.5)=0
Wy multiply elements
10x^2=0
a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$

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