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5(x-1)(x-7)=0
We multiply parentheses ..
5(+x^2-7x-1x+7)=0
We multiply parentheses
5x^2-35x-5x+35=0
We add all the numbers together, and all the variables
5x^2-40x+35=0
a = 5; b = -40; c = +35;
Δ = b2-4ac
Δ = -402-4·5·35
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-30}{2*5}=\frac{10}{10} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+30}{2*5}=\frac{70}{10} =7 $
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