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5(x-1)+(2x+9)3-2(x-4)=(3x-1)4-(4x-3)
We move all terms to the left:
5(x-1)+(2x+9)3-2(x-4)-((3x-1)4-(4x-3))=0
We multiply parentheses
5x+6x-2x-((3x-1)4-(4x-3))-5+27+8=0
We calculate terms in parentheses: -((3x-1)4-(4x-3)), so:We add all the numbers together, and all the variables
(3x-1)4-(4x-3)
We multiply parentheses
12x-(4x-3)-4
We get rid of parentheses
12x-4x+3-4
We add all the numbers together, and all the variables
8x-1
Back to the equation:
-(8x-1)
9x-(8x-1)+30=0
We get rid of parentheses
9x-8x+1+30=0
We add all the numbers together, and all the variables
x+31=0
We move all terms containing x to the left, all other terms to the right
x=-31
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