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5(x-1)+1=2x+3(-1+x)
We move all terms to the left:
5(x-1)+1-(2x+3(-1+x))=0
We add all the numbers together, and all the variables
5(x-1)-(2x+3(x-1))+1=0
We multiply parentheses
5x-(2x+3(x-1))-5+1=0
We calculate terms in parentheses: -(2x+3(x-1)), so:We add all the numbers together, and all the variables
2x+3(x-1)
We multiply parentheses
2x+3x-3
We add all the numbers together, and all the variables
5x-3
Back to the equation:
-(5x-3)
5x-(5x-3)-4=0
We get rid of parentheses
5x-5x+3-4=0
We add all the numbers together, and all the variables
-1!=0
There is no solution for this equation
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