5(x-1)+2(x-3)=-4(x-2)+10(x+4)

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Solution for 5(x-1)+2(x-3)=-4(x-2)+10(x+4) equation: 



5(x-1)+2(x-3)=-4(x-2)+10(x+4)

We move all terms to the left:

5(x-1)+2(x-3)-(-4(x-2)+10(x+4))=0

We multiply parentheses

5x+2x-(-4(x-2)+10(x+4))-5-6=0



We calculate terms in parentheses: -(-4(x-2)+10(x+4)), so:

-4(x-2)+10(x+4)

We multiply parentheses

-4x+10x+8+40

We add all the numbers together, and all the variables

6x+48

Back to the equation:

-(6x+48)



We add all the numbers together, and all the variables

7x-(6x+48)-11=0

We get rid of parentheses

7x-6x-48-11=0

We add all the numbers together, and all the variables

x-59=0

We move all terms containing x to the left, all other terms to the right

x=59

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