5(x-1)+4(x+2)=3(x-11)

Solution for 5(x-1)+4(x+2)=3(x-11) equation:

5(x-1)+4(x+2)=3(x-11)

We move all terms to the left:

5(x-1)+4(x+2)-(3(x-11))=0

We multiply parentheses

5x+4x-(3(x-11))-5+8=0


We calculate terms in parentheses: -(3(x-11)), so:

3(x-11)

We multiply parentheses

3x-33

Back to the equation:

-(3x-33)


We add all the numbers together, and all the variables

9x-(3x-33)+3=0

We get rid of parentheses

9x-3x+33+3=0

We add all the numbers together, and all the variables

6x+36=0

We move all terms containing x to the left, all other terms to the right

6x=-36

x=-36/6

x=-6