5(x-1)+6x=1/2(8x-4)

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Solution for 5(x-1)+6x=1/2(8x-4) equation: 



5(x-1)+6x=1/2(8x-4)

We move all terms to the left:

5(x-1)+6x-(1/2(8x-4))=0



Domain of the equation: 2(8x-4))!=0

x∈R



We add all the numbers together, and all the variables

6x+5(x-1)-(1/2(8x-4))=0

We multiply parentheses

6x+5x-(1/2(8x-4))-5=0

We multiply all the terms by the denominator


6x*2(8x-4))+5x*2(8x-4))-(1-5*2(8x-4))=0

We add all the numbers together, and all the variables

6x*2(8x-4))+5x*2(8x-4))-(1-5*2(8x=0

Wy multiply elements

24x^3(8-4))-(1-5*2(8x=0

We do not support expression: x^3(8

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