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5(x-1)-1=3x+2(-2+x
We move all terms to the left:
5(x-1)-1-(3x+2(-2+x)=0
We add all the numbers together, and all the variables
5(x-1)-(3x+2(x-2)-1=0
We multiply parentheses
5x-(3x+2(x-2)-1-5=0
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