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5(x-1)-4=3(x-2)+3
We move all terms to the left:
5(x-1)-4-(3(x-2)+3)=0
We multiply parentheses
5x-(3(x-2)+3)-5-4=0
We calculate terms in parentheses: -(3(x-2)+3), so:We add all the numbers together, and all the variables
3(x-2)+3
We multiply parentheses
3x-6+3
We add all the numbers together, and all the variables
3x-3
Back to the equation:
-(3x-3)
5x-(3x-3)-9=0
We get rid of parentheses
5x-3x+3-9=0
We add all the numbers together, and all the variables
2x-6=0
We move all terms containing x to the left, all other terms to the right
2x=6
x=6/2
x=3
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