5(x-1)-8=x-4(2x-1)

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Solution for 5(x-1)-8=x-4(2x-1) equation: 



5(x-1)-8=x-4(2x-1)

We move all terms to the left:

5(x-1)-8-(x-4(2x-1))=0

We multiply parentheses

5x-(x-4(2x-1))-5-8=0



We calculate terms in parentheses: -(x-4(2x-1)), so:

x-4(2x-1)

We multiply parentheses

x-8x+4

We add all the numbers together, and all the variables

-7x+4

Back to the equation:

-(-7x+4)



We add all the numbers together, and all the variables

5x-(-7x+4)-13=0

We get rid of parentheses

5x+7x-4-13=0

We add all the numbers together, and all the variables

12x-17=0

We move all terms containing x to the left, all other terms to the right

12x=17

x=17/12

x=1+5/12

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