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5(x-1)=2(2x+3)
We move all terms to the left:
5(x-1)-(2(2x+3))=0
We multiply parentheses
5x-(2(2x+3))-5=0
We calculate terms in parentheses: -(2(2x+3)), so:We get rid of parentheses
2(2x+3)
We multiply parentheses
4x+6
Back to the equation:
-(4x+6)
5x-4x-6-5=0
We add all the numbers together, and all the variables
x-11=0
We move all terms containing x to the left, all other terms to the right
x=11
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