5(x-1)=2(x+3)+1

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Solution for 5(x-1)=2(x+3)+1 equation: 



5(x-1)=2(x+3)+1

We move all terms to the left:

5(x-1)-(2(x+3)+1)=0

We multiply parentheses

5x-(2(x+3)+1)-5=0



We calculate terms in parentheses: -(2(x+3)+1), so:

2(x+3)+1

We multiply parentheses

2x+6+1

We add all the numbers together, and all the variables

2x+7

Back to the equation:

-(2x+7)



We get rid of parentheses

5x-2x-7-5=0

We add all the numbers together, and all the variables

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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