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5(x-1)=3-(3x-7)+(4-2x)
We move all terms to the left:
5(x-1)-(3-(3x-7)+(4-2x))=0
We add all the numbers together, and all the variables
5(x-1)-(3-(3x-7)+(-2x+4))=0
We multiply parentheses
5x-(3-(3x-7)+(-2x+4))-5=0
We calculate terms in parentheses: -(3-(3x-7)+(-2x+4)), so:We get rid of parentheses
3-(3x-7)+(-2x+4)
determiningTheFunctionDomain -(3x-7)+(-2x+4)+3
We get rid of parentheses
-3x-2x+7+4+3
We add all the numbers together, and all the variables
-5x+14
Back to the equation:
-(-5x+14)
5x+5x-14-5=0
We add all the numbers together, and all the variables
10x-19=0
We move all terms containing x to the left, all other terms to the right
10x=19
x=19/10
x=1+9/10
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