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5(x-1)=4x(x+1)
We move all terms to the left:
5(x-1)-(4x(x+1))=0
We multiply parentheses
5x-(4x(x+1))-5=0
We calculate terms in parentheses: -(4x(x+1)), so:We get rid of parentheses
4x(x+1)
We multiply parentheses
4x^2+4x
Back to the equation:
-(4x^2+4x)
-4x^2+5x-4x-5=0
We add all the numbers together, and all the variables
-4x^2+x-5=0
a = -4; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·(-4)·(-5)
Δ = -79
Delta is less than zero, so there is no solution for the equation
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