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5(x-1)=5/4x
We move all terms to the left:
5(x-1)-(5/4x)=0
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5(x-1)-(+5/4x)=0
We multiply parentheses
5x-(+5/4x)-5=0
We get rid of parentheses
5x-5/4x-5=0
We multiply all the terms by the denominator
5x*4x-5*4x-5=0
Wy multiply elements
20x^2-20x-5=0
a = 20; b = -20; c = -5;
Δ = b2-4ac
Δ = -202-4·20·(-5)
Δ = 800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{800}=\sqrt{400*2}=\sqrt{400}*\sqrt{2}=20\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20\sqrt{2}}{2*20}=\frac{20-20\sqrt{2}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20\sqrt{2}}{2*20}=\frac{20+20\sqrt{2}}{40} $
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