5(x-1)=7x-2(x+1)-3

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Solution for 5(x-1)=7x-2(x+1)-3 equation: 



5(x-1)=7x-2(x+1)-3

We move all terms to the left:

5(x-1)-(7x-2(x+1)-3)=0

We multiply parentheses

5x-(7x-2(x+1)-3)-5=0



We calculate terms in parentheses: -(7x-2(x+1)-3), so:

7x-2(x+1)-3

We multiply parentheses

7x-2x-2-3

We add all the numbers together, and all the variables

5x-5

Back to the equation:

-(5x-5)



We get rid of parentheses

5x-5x+5-5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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