5(x-12)+8=3(x+2)-40

Solution for 5(x-12)+8=3(x+2)-40 equation:

5(x-12)+8=3(x+2)-40

We move all terms to the left:

5(x-12)+8-(3(x+2)-40)=0

We multiply parentheses

5x-(3(x+2)-40)-60+8=0


We calculate terms in parentheses: -(3(x+2)-40), so:

3(x+2)-40

We multiply parentheses

3x+6-40

We add all the numbers together, and all the variables

3x-34

Back to the equation:

-(3x-34)


We add all the numbers together, and all the variables

5x-(3x-34)-52=0

We get rid of parentheses

5x-3x+34-52=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9