5(x-12)=9x(2x+5)

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Solution for 5(x-12)=9x(2x+5) equation: 



5(x-12)=9x(2x+5)

We move all terms to the left:

5(x-12)-(9x(2x+5))=0

We multiply parentheses

5x-(9x(2x+5))-60=0



We calculate terms in parentheses: -(9x(2x+5)), so:

9x(2x+5)

We multiply parentheses

18x^2+45x

Back to the equation:

-(18x^2+45x)



We get rid of parentheses

-18x^2+5x-45x-60=0

We add all the numbers together, and all the variables

-18x^2-40x-60=0

a = -18; b = -40; c = -60;
Δ = b2-4ac
Δ = -402-4·(-18)·(-60)
Δ = -2720
Delta is less than zero, so there is no solution for the equation

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