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5(x-13)=10-(2x+5)
We move all terms to the left:
5(x-13)-(10-(2x+5))=0
We multiply parentheses
5x-(10-(2x+5))-65=0
We calculate terms in parentheses: -(10-(2x+5)), so:We get rid of parentheses
10-(2x+5)
determiningTheFunctionDomain -(2x+5)+10
We get rid of parentheses
-2x-5+10
We add all the numbers together, and all the variables
-2x+5
Back to the equation:
-(-2x+5)
5x+2x-5-65=0
We add all the numbers together, and all the variables
7x-70=0
We move all terms containing x to the left, all other terms to the right
7x=70
x=70/7
x=10
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