5(x-2)+(-3)=7(1-x)+8x

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Solution for 5(x-2)+(-3)=7(1-x)+8x equation: 



5(x-2)+(-3)=7(1-x)+8x

We move all terms to the left:

5(x-2)+(-3)-(7(1-x)+8x)=0

We add all the numbers together, and all the variables

5(x-2)-(7(-1x+1)+8x)+(-3)=0

We add all the numbers together, and all the variables

5(x-2)-(7(-1x+1)+8x)-3=0

We multiply parentheses

5x-(7(-1x+1)+8x)-10-3=0



We calculate terms in parentheses: -(7(-1x+1)+8x), so:

7(-1x+1)+8x

We add all the numbers together, and all the variables

8x+7(-1x+1)

We multiply parentheses

8x-7x+7

We add all the numbers together, and all the variables

x+7

Back to the equation:

-(x+7)



We add all the numbers together, and all the variables

5x-(x+7)-13=0

We get rid of parentheses

5x-x-7-13=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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