5(x-2)+1=1/2(10x-4)+8

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Solution for 5(x-2)+1=1/2(10x-4)+8 equation: 



5(x-2)+1=1/2(10x-4)+8

We move all terms to the left:

5(x-2)+1-(1/2(10x-4)+8)=0



Domain of the equation: 2(10x-4)+8)!=0

x∈R



We multiply parentheses

5x-(1/2(10x-4)+8)-10+1=0

We multiply all the terms by the denominator


5x*2(10x-4)-10*2(10x-4)+8)+1*2(10x+8)-(1-4)+8)=0

We add all the numbers together, and all the variables

5x*2(10x-4)-10*2(10x-4)+8)+1*2(10x+8)-(-3)+8)=0

We add all the numbers together, and all the variables

5x*2(10x-4)-10*2(10x-4)+8)+1*2(10x=0

Wy multiply elements

10x^2(1-20x(1+8)+1*2(10x=0

We add all the numbers together, and all the variables

10x^2(1-20x9+1*2(10x=0

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