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5(x-2)+1=3x+2(-5+x)
We move all terms to the left:
5(x-2)+1-(3x+2(-5+x))=0
We add all the numbers together, and all the variables
5(x-2)-(3x+2(x-5))+1=0
We multiply parentheses
5x-(3x+2(x-5))-10+1=0
We calculate terms in parentheses: -(3x+2(x-5)), so:We add all the numbers together, and all the variables
3x+2(x-5)
We multiply parentheses
3x+2x-10
We add all the numbers together, and all the variables
5x-10
Back to the equation:
-(5x-10)
5x-(5x-10)-9=0
We get rid of parentheses
5x-5x+10-9=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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