5(x-2)+2(x+3)-6=20

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Solution for 5(x-2)+2(x+3)-6=20 equation: 



5(x-2)+2(x+3)-6=20

We move all terms to the left:

5(x-2)+2(x+3)-6-(20)=0

We add all the numbers together, and all the variables

5(x-2)+2(x+3)-26=0

We multiply parentheses

5x+2x-10+6-26=0

We add all the numbers together, and all the variables

7x-30=0

We move all terms containing x to the left, all other terms to the right

7x=30

x=30/7

x=4+2/7

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