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5(x-2)+2=2x+3(-3+x)
We move all terms to the left:
5(x-2)+2-(2x+3(-3+x))=0
We add all the numbers together, and all the variables
5(x-2)-(2x+3(x-3))+2=0
We multiply parentheses
5x-(2x+3(x-3))-10+2=0
We calculate terms in parentheses: -(2x+3(x-3)), so:We add all the numbers together, and all the variables
2x+3(x-3)
We multiply parentheses
2x+3x-9
We add all the numbers together, and all the variables
5x-9
Back to the equation:
-(5x-9)
5x-(5x-9)-8=0
We get rid of parentheses
5x-5x+9-8=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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