5(x-2)+2=8(x-3)+1

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Solution for 5(x-2)+2=8(x-3)+1 equation: 



5(x-2)+2=8(x-3)+1

We move all terms to the left:

5(x-2)+2-(8(x-3)+1)=0

We multiply parentheses

5x-(8(x-3)+1)-10+2=0



We calculate terms in parentheses: -(8(x-3)+1), so:

8(x-3)+1

We multiply parentheses

8x-24+1

We add all the numbers together, and all the variables

8x-23

Back to the equation:

-(8x-23)



We add all the numbers together, and all the variables

5x-(8x-23)-8=0

We get rid of parentheses

5x-8x+23-8=0

We add all the numbers together, and all the variables

-3x+15=0

We move all terms containing x to the left, all other terms to the right

-3x=-15

x=-15/-3

x=+5

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