5(x-2)+2x=7(x+3)-31

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Solution for 5(x-2)+2x=7(x+3)-31 equation: 


Simplifying
5(x + -2) + 2x = 7(x + 3) + -31

Reorder the terms:
5(-2 + x) + 2x = 7(x + 3) + -31
(-2 * 5 + x * 5) + 2x = 7(x + 3) + -31
(-10 + 5x) + 2x = 7(x + 3) + -31

Combine like terms: 5x + 2x = 7x
-10 + 7x = 7(x + 3) + -31

Reorder the terms:
-10 + 7x = 7(3 + x) + -31
-10 + 7x = (3 * 7 + x * 7) + -31
-10 + 7x = (21 + 7x) + -31

Reorder the terms:
-10 + 7x = 21 + -31 + 7x

Combine like terms: 21 + -31 = -10
-10 + 7x = -10 + 7x

Add '10' to each side of the equation.
-10 + 10 + 7x = -10 + 10 + 7x

Combine like terms: -10 + 10 = 0
0 + 7x = -10 + 10 + 7x
7x = -10 + 10 + 7x

Combine like terms: -10 + 10 = 0
7x = 0 + 7x
7x = 7x

Add '-7x' to each side of the equation.
7x + -7x = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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