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5(x-2)+3(1/3x+1)=2(3x-4)+2
We move all terms to the left:
5(x-2)+3(1/3x+1)-(2(3x-4)+2)=0
Domain of the equation: 3x+1)!=0We multiply parentheses
x∈R
5x+3x-(2(3x-4)+2)-10+3=0
We calculate terms in parentheses: -(2(3x-4)+2), so:We add all the numbers together, and all the variables
2(3x-4)+2
We multiply parentheses
6x-8+2
We add all the numbers together, and all the variables
6x-6
Back to the equation:
-(6x-6)
8x-(6x-6)-7=0
We get rid of parentheses
8x-6x+6-7=0
We add all the numbers together, and all the variables
2x-1=0
We move all terms containing x to the left, all other terms to the right
2x=1
x=1/2
x=1/2
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