5(x-2)+3(1/3x+1)=2(3x-4)+2

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Solution for 5(x-2)+3(1/3x+1)=2(3x-4)+2 equation: 



5(x-2)+3(1/3x+1)=2(3x-4)+2

We move all terms to the left:

5(x-2)+3(1/3x+1)-(2(3x-4)+2)=0



Domain of the equation: 3x+1)!=0

x∈R



We multiply parentheses

5x+3x-(2(3x-4)+2)-10+3=0



We calculate terms in parentheses: -(2(3x-4)+2), so:

2(3x-4)+2

We multiply parentheses

6x-8+2

We add all the numbers together, and all the variables

6x-6

Back to the equation:

-(6x-6)



We add all the numbers together, and all the variables

8x-(6x-6)-7=0

We get rid of parentheses

8x-6x+6-7=0

We add all the numbers together, and all the variables

2x-1=0

We move all terms containing x to the left, all other terms to the right

2x=1

x=1/2

x=1/2

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