5(x-2)+3(x+4)=3(2x-8)-10

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Solution for 5(x-2)+3(x+4)=3(2x-8)-10 equation: 



5(x-2)+3(x+4)=3(2x-8)-10

We move all terms to the left:

5(x-2)+3(x+4)-(3(2x-8)-10)=0

We multiply parentheses

5x+3x-(3(2x-8)-10)-10+12=0



We calculate terms in parentheses: -(3(2x-8)-10), so:

3(2x-8)-10

We multiply parentheses

6x-24-10

We add all the numbers together, and all the variables

6x-34

Back to the equation:

-(6x-34)



We add all the numbers together, and all the variables

8x-(6x-34)+2=0

We get rid of parentheses

8x-6x+34+2=0

We add all the numbers together, and all the variables

2x+36=0

We move all terms containing x to the left, all other terms to the right

2x=-36

x=-36/2

x=-18

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