5(x-2)+3x+12=6x+2(x+1)

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Solution for 5(x-2)+3x+12=6x+2(x+1) equation: 



5(x-2)+3x+12=6x+2(x+1)

We move all terms to the left:

5(x-2)+3x+12-(6x+2(x+1))=0

We add all the numbers together, and all the variables

3x+5(x-2)-(6x+2(x+1))+12=0

We multiply parentheses

3x+5x-(6x+2(x+1))-10+12=0



We calculate terms in parentheses: -(6x+2(x+1)), so:

6x+2(x+1)

We multiply parentheses

6x+2x+2

We add all the numbers together, and all the variables

8x+2

Back to the equation:

-(8x+2)



We add all the numbers together, and all the variables

8x-(8x+2)+2=0

We get rid of parentheses

8x-8x-2+2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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