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5(x-2)+3x=(x+4)
We move all terms to the left:
5(x-2)+3x-((x+4))=0
We add all the numbers together, and all the variables
3x+5(x-2)-((x+4))=0
We multiply parentheses
3x+5x-((x+4))-10=0
We calculate terms in parentheses: -((x+4)), so:We add all the numbers together, and all the variables
(x+4)
We get rid of parentheses
x+4
Back to the equation:
-(x+4)
8x-(x+4)-10=0
We get rid of parentheses
8x-x-4-10=0
We add all the numbers together, and all the variables
7x-14=0
We move all terms containing x to the left, all other terms to the right
7x=14
x=14/7
x=2
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