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5(x-2)+3x=2(3x+4)=
We move all terms to the left:
5(x-2)+3x-(2(3x+4))=0
We add all the numbers together, and all the variables
3x+5(x-2)-(2(3x+4))=0
We multiply parentheses
3x+5x-(2(3x+4))-10=0
We calculate terms in parentheses: -(2(3x+4)), so:We add all the numbers together, and all the variables
2(3x+4)
We multiply parentheses
6x+8
Back to the equation:
-(6x+8)
8x-(6x+8)-10=0
We get rid of parentheses
8x-6x-8-10=0
We add all the numbers together, and all the variables
2x-18=0
We move all terms containing x to the left, all other terms to the right
2x=18
x=18/2
x=9
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