5(x-2)+6(x+1)-2=5(x-4)

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Solution for 5(x-2)+6(x+1)-2=5(x-4) equation: 



5(x-2)+6(x+1)-2=5(x-4)

We move all terms to the left:

5(x-2)+6(x+1)-2-(5(x-4))=0

We multiply parentheses

5x+6x-(5(x-4))-10+6-2=0



We calculate terms in parentheses: -(5(x-4)), so:

5(x-4)

We multiply parentheses

5x-20

Back to the equation:

-(5x-20)



We add all the numbers together, and all the variables

11x-(5x-20)-6=0

We get rid of parentheses

11x-5x+20-6=0

We add all the numbers together, and all the variables

6x+14=0

We move all terms containing x to the left, all other terms to the right

6x=-14

x=-14/6

x=-2+1/3

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