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5(x-2)+6=3(x+4)
We move all terms to the left:
5(x-2)+6-(3(x+4))=0
We multiply parentheses
5x-(3(x+4))-10+6=0
We calculate terms in parentheses: -(3(x+4)), so:We add all the numbers together, and all the variables
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
5x-(3x+12)-4=0
We get rid of parentheses
5x-3x-12-4=0
We add all the numbers together, and all the variables
2x-16=0
We move all terms containing x to the left, all other terms to the right
2x=16
x=16/2
x=8
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