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5(x-2)+6=3x-(x+13)
We move all terms to the left:
5(x-2)+6-(3x-(x+13))=0
We multiply parentheses
5x-(3x-(x+13))-10+6=0
We calculate terms in parentheses: -(3x-(x+13)), so:We add all the numbers together, and all the variables
3x-(x+13)
We get rid of parentheses
3x-x-13
We add all the numbers together, and all the variables
2x-13
Back to the equation:
-(2x-13)
5x-(2x-13)-4=0
We get rid of parentheses
5x-2x+13-4=0
We add all the numbers together, and all the variables
3x+9=0
We move all terms containing x to the left, all other terms to the right
3x=-9
x=-9/3
x=-3
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