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5(x-2)+9=2(x-2)+6x
We move all terms to the left:
5(x-2)+9-(2(x-2)+6x)=0
We multiply parentheses
5x-(2(x-2)+6x)-10+9=0
We calculate terms in parentheses: -(2(x-2)+6x), so:We add all the numbers together, and all the variables
2(x-2)+6x
We add all the numbers together, and all the variables
6x+2(x-2)
We multiply parentheses
6x+2x-4
We add all the numbers together, and all the variables
8x-4
Back to the equation:
-(8x-4)
5x-(8x-4)-1=0
We get rid of parentheses
5x-8x+4-1=0
We add all the numbers together, and all the variables
-3x+3=0
We move all terms containing x to the left, all other terms to the right
-3x=-3
x=-3/-3
x=1
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