5(x-2)+x=6(x-3)+8

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Solution for 5(x-2)+x=6(x-3)+8 equation: 


Simplifying
5(x + -2) + x = 6(x + -3) + 8

Reorder the terms:
5(-2 + x) + x = 6(x + -3) + 8
(-2 * 5 + x * 5) + x = 6(x + -3) + 8
(-10 + 5x) + x = 6(x + -3) + 8

Combine like terms: 5x + x = 6x
-10 + 6x = 6(x + -3) + 8

Reorder the terms:
-10 + 6x = 6(-3 + x) + 8
-10 + 6x = (-3 * 6 + x * 6) + 8
-10 + 6x = (-18 + 6x) + 8

Reorder the terms:
-10 + 6x = -18 + 8 + 6x

Combine like terms: -18 + 8 = -10
-10 + 6x = -10 + 6x

Add '10' to each side of the equation.
-10 + 10 + 6x = -10 + 10 + 6x

Combine like terms: -10 + 10 = 0
0 + 6x = -10 + 10 + 6x
6x = -10 + 10 + 6x

Combine like terms: -10 + 10 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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