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5(x-2)-(4x-2)=2+(2-x)
We move all terms to the left:
5(x-2)-(4x-2)-(2+(2-x))=0
We add all the numbers together, and all the variables
5(x-2)-(4x-2)-(2+(-1x+2))=0
We multiply parentheses
5x-(4x-2)-(2+(-1x+2))-10=0
We get rid of parentheses
5x-4x-(2+(-1x+2))+2-10=0
We calculate terms in parentheses: -(2+(-1x+2)), so:We add all the numbers together, and all the variables
2+(-1x+2)
determiningTheFunctionDomain (-1x+2)+2
We get rid of parentheses
-1x+2+2
We add all the numbers together, and all the variables
-1x+4
Back to the equation:
-(-1x+4)
x-(-1x+4)-8=0
We get rid of parentheses
x+1x-4-8=0
We add all the numbers together, and all the variables
2x-12=0
We move all terms containing x to the left, all other terms to the right
2x=12
x=12/2
x=6
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